\color{rgb(0,0,0)}\begin{array}{l}
\vec{u}\left( \begin{array}{c}
1
\\ -4
\\ 3
\end{array} \right)
\\ A(0;2;-2)
\\\overrightarrow {AM}=t\vec{u}
\end{array}
$$\color{rgb(255,0,0)}\vec{i}$$
$$\color{rgb(0,127,0)}-4\vec{j}$$
$$\color{rgb(0,0,255)}3\vec{k}$$