    \begin{exercice} Calculer $\displaystyle \int_0^3 2 \, \textrm{d}x$ et $\displaystyle \int_0^{4} 2\textrm{e}^{-2t} \, \textrm{d}t$.
    
    \begin{corrige}
    \begin{itemize}
      \item $\displaystyle \int_0^3 2 \, \textrm{d}x=[2x]^3_0=2\times 3-2\times 0=6$
      \item ${\displaystyle \int_0^{4} 2\textrm{e}^{-2t} \, \textrm{d}t=[-\textrm{e}^{-2t}]^4_0=-\textrm{e}^{-2\times 4}-\left(-\textrm{e}^{-2\times 0}\right)}$

          $=-\textrm{e}^{-8}+1$.
    \end{itemize}
    \end{corrige}
    \end{exercice}

