\begin{tableau}[pr]{\linewidth}
  \\ \hline %%%%%%%%%%%%%%%%%%%%%%P31
 \begin{tikzpicture}[general, xscale=0.7, yscale=0.5]
 \draw (0,-1)--(2,0)--(0,1)--(-2,0)--cycle;
 \draw (0,-1) node[below] {$A$};
 \draw (2,0) node[right] {$B$};
 \draw (0,1) node[above] {$C$};
 \draw (-2,0) node[left] {$D$};
 \draw (0,0) rectangle (0.3,0.3);
 \draw (2,0)--(-2,0);
 \draw (0,-1)--(0,1);
\draw (-3,-1.5) node[right]{$ABCD$};
\draw (-3,-2.2) node[right]{est un parallélogramme};
\end{tikzpicture} &
  \propriete{}
 Si un parallélogramme a ses diagonales perpendiculaires alors c'est un losange.
& Ici, $ABCD$ est un parallélogramme et $(AC)\perp(BD)$. 

Donc $ABCD$ est un losange.
\end{tableau}
