\begin{tableau}[pr]{\linewidth}
  \\ \hline %%%%%%%%%%%%%%%%%%%%%%P24
\begin{tikzpicture}[general, scale=0.6]
 \draw (0,0)--(4,1)--(5,3)--(1,2)--cycle;
 \draw (0,0)--(5,3);
 \draw (4,1)--(1,2);
 \draw (0,0) node[below left]{$A$};
 \draw (4,1) node[below right]{$B$};
 \draw (4.7,3) node[above right]{$C$};
 \draw (1,2) node[above left]{$D$};
 \draw (1.25,0.75) node[color=A1,rotate=120.96] {$\approx$};
 \draw (1.75,1.75) node[color=B1,rotate=-120.96] {$\infty$};
 \draw (3.75,2.25) node[color=A1,rotate=120.96] {$\approx$};
 \draw (3.25,1.25) node[color=B1,rotate=-120.96] {$\infty$};
\end{tikzpicture}
 &
  \propriete{}
Si un quadrilatère a ses diagonales qui se coupent en leur milieu alors c'est un parallélogramme.    
& Ici, $[AC]$ et $[BD]$ se coupent en leur milieu.

Donc, $ABCD$ est un parallélogramme. 
\end{tableau}
