\begin{tableau}[pr]{\linewidth}
  \\ \hline %%%%%%%%%%%%%%%%%%%%%%P68
\begin{tikzpicture}[general, scale=0.3]
\clip(-3.2,-6.5) rectangle (8,3);
\draw[color=J1,fill=J1] (4.91,-4.72) -- (4.49,-4.65) -- (4.42,-5.07) -- (4.84,-5.14) -- cycle; 
\draw[color=J1,fill=J1] (2.6,0.6) -- (2.9,0.3) -- (3.2,0.6) -- (2.9,0.9) -- cycle; 
 \draw [domain=-2.0:8] plot(\x,{(-52-2*\x)/12});
\draw [domain=-2.0:8] plot(\x,{(-16--8*\x)/8});
\draw [domain=-2:8, color=A1, very thick] plot(\x,{(-3.2--0.31*\x)/0.95});
\draw (-2,-4) node[left] {$O$};
\draw (5.42,-1.62) node[above] {$B$};
\draw (2.9,0.9) node[above] {$C$};
\draw (4.84,-5.14) node[below] {$D$};
\draw (4.84,3) node[below] {$x$};
\draw (8,-6) node[above left] {$y$};
\draw[dashed] (2.9,0.9)-- (5.42,-1.62);
\draw[dashed] (5.42,-1.62)-- (4.84,-5.14);
   \draw (4.16,-0.3) node[color=A1, rotate=45]{$\approx$};
   \draw (5.13,-3.32) node[color=A1, rotate=-5]{$\approx$};
\end{tikzpicture} &
  \propriete{}
 Si un point est situé à la même distance des côtés d'un angle alors il appartient à la bissectrice de cet angle.&
 Ici, $BC=BD$, $(OC)\perp(BC)$ et $(BD)\perp (OD)$.
 
 Donc, $[OB)$ est la bissectrice de l'angle $\widehat{COD}$
\end{tableau}
