\begin{exercice}[Camembert]
Un camembert est modélisé par un cylindre \\de révolution d'axe $(OO')$.
\vspace{-0.3em}
\begin{center}
\begin{tikzpicture}[general, yscale=0.55, xscale=0.75]
\draw[fill=C4] (1,4) .. controls +(0,-0.5)and +(0,-0.5) .. (6,4);
\draw[fill=C4] (1,4) .. controls +(0,0.5)and +(0,0.5) .. (6,4);
\draw[fill=C4] (1,1) .. controls +(0,-0.5)and +(0,-0.5) .. (6,1);
\draw[dashed, fill=C4] (1,1) .. controls +(0,0.5)and +(0,0.5) .. (6,1);
\draw (1,1)--(1,4);
\draw (6,1)--(6,4);
\draw (6,1) node {$\bullet$};;
\draw (6,1) node[right] {$B$};
\draw (1,1) node {$\bullet$};;
\draw (1,1) node[left] {$A$};
\draw (1,4) node {$\bullet$};;
\draw (1,4) node[left] {$D$};
\draw (6,4) node {$\bullet$};;
\draw (6,4) node[right] {$C$};
\draw (3.5,4) node {{\boldmath $+$}};
\draw (3.5,4) node[right] {$O'$};
\draw (3.5,1) node {{\boldmath $+$}};
\draw (3.5,1) node[right] {$O$};
\draw (5.25,4.27) node {$\bullet$};;
\draw (5.25,4.27) node[above] {$E$};
\draw (5.25,1.27) node {$\bullet$};;
\draw (5.25,1.27) node[above] {$F$};
\draw (4.33,3.65) node {$\bullet$};;
\draw (4.33,3.65) node[below] {$G$};
% \end{scriptsize}
\end{tikzpicture}
\end{center}
\vspace{-1em}
\begin{enumerate}
    \item Citer deux plans parallèles.
    \item Citer trois plans sécants avec le plan ($ABF$).
\end{enumerate}
\vspace{-1.5em}
 On coupe le cylindre suivant la droite $(GE)$ parallèlement à
$(CB)$. Le point $F$ est tel que $(EF)//(CB)$.
\begin{enumerate}
\setcounter{enumi}{2}
\item Quelle sera la nature de la section obtenue ?
\item Que peut-on dire des plans $(EFG)$ et $(EOO')$ ?
\end{enumerate}
\end{exercice}

