\begin{exercice*}\ExerciceRefMethode{2F3_M_dresser_tableau}\label{2F3_E_dresser_tableau}

 Associer chaque courbe à son tableau de variations.
 
 \begin{tikzpicture}[general, scale=0.65]
  \draw[quadrillage55] (-3,-2)grid(3,2);
  \axeX{-3}{3}{1}
  \axeY{-2}{2}{1}
  \origine
 \draw (-2.5, 1.5) node[draw, circle, color=C1] {$a$};
  \draw[epais, color=A1] (-2.5,-2)--(3,1);
 \end{tikzpicture}
 \hfill
 \begin{tikzpicture}[general, scale=0.65]
  \draw[quadrillage55] (-3,-2)grid(3,2);
  \axeX{-3}{3}{1}
  \axeY{-2}{2}{1}
  \origine
  \draw (-2.5, 1.5) node[draw, circle, color=C1] {$b$};
  \draw[epais, color=A1] (-2,2)--(2.5,-2);
 \end{tikzpicture}
 
 \begin{tikzpicture}[general, scale=0.65]
  \draw[quadrillage55] (-3,-2)grid(3,2);
  \axeX{-3}{3}{1}
  \axeY{-2}{2}{1}
  \origine
  \draw (-2.5, 1.5) node[draw, circle, color=C1] {$c$};
  \draw[epais, color=A1] (-2.5,-2)--(3,-0.5);
 \end{tikzpicture} 
 \hfill
 \begin{tikzpicture}[general, scale=0.65]
  \draw[quadrillage55] (-3,-2)grid(3,2);
  \axeX{-3}{3}{1}
  \axeY{-2}{2}{1}
  \origine
  \draw (-2.5, 1.5) node[draw, circle, color=C1] {$d$};
  \draw[epais, color=A1] (-2,2)--(3,0.5);
 \end{tikzpicture}
 \begin{colenumerate}{2}
  \item \begin{tikzpicture}[general,yscale=0.75]
\tkzTabInit[lgt=1,espcl=1.5, color, colorC=H4, colorV=H4, colorL=H4, colorT=A4, lw=0.3mm]
{ $x$ / 1,  $f(x)$ / 2}{ $-2$,$3$}
\tkzTabVar{+/2,-/$0{,}5$}
\end{tikzpicture}
  \item \begin{tikzpicture}[general,yscale=0.75]
\tkzTabInit[lgt=1,espcl=1.5, color, colorC=H4, colorV=H4, colorL=H4, colorT=A4, lw=0.3mm]
{ $x$ / 1,  $f(x)$ / 2}{ $-2{,}5$,$3$}
\tkzTabVar{-/$-2$,+/$-0{,}5$}
\end{tikzpicture}
  \item \begin{tikzpicture}[general,yscale=0.75]
\tkzTabInit[lgt=1.04,espcl=1.5, color, colorC=H4, colorV=H4, colorL=H4, colorT=A4, lw=0.3mm]
{ $x$ / 1,  $f(x)$ / 2}{ $-2{,}5$,$3$}
\tkzTabVar{-/$-2$,+/$1$}
\end{tikzpicture}
  \item \begin{tikzpicture}[general,yscale=0.75]
\tkzTabInit[lgt=1.04,espcl=1.5, color, colorC=H4, colorV=H4, colorL=H4, colorT=A4, lw=0.3mm]
{ $x$ / 1,  $f(x)$ / 2}{ $-2$,$2{,}5$}
\tkzTabVar{+/2,-/$-2$}
\end{tikzpicture}
 \end{colenumerate}

\begin{corrige}
\begin{colenumerate}{2}
\item $d.$
\item $c.$
\item $a.$
\item $b.$
\end{colenumerate}
\end{corrige}
\end{exercice*}
